Borderou de evaluare (job #2338249)
Utilizator | Data | 7 februarie 2019 11:15:52 | |
---|---|---|---|
Problema | Elicoptere | Status | done |
Runda | Arhiva de probleme | Compilator | cpp-64 | Vezi sursa |
Scor | 0 |
Raport evaluator
Eroare de compilare:
main.cpp: In function 'long double vertical_dist(long double, long double, long double, long double, long double, long double)':
main.cpp:5:14: error: unable to find numeric literal operator 'operator""d'
#define INF (1d)2e9
^
main.cpp:39:17: note: in expansion of macro 'INF'
else return INF;
^~~
main.cpp:5:14: note: use -std=gnu++11 or -fext-numeric-literals to enable more built-in suffixes
#define INF (1d)2e9
^
main.cpp:39:17: note: in expansion of macro 'INF'
else return INF;
^~~
main.cpp:5:17: error: expected ';' before numeric constant
#define INF (1d)2e9
^
main.cpp:39:17: note: in expansion of macro 'INF'
else return INF;
^~~
main.cpp:39:20: warning: statement has no effect [-Wunused-value]
else return INF;
^
main.cpp: In function 'long double horizontally_dist(long double, long double, long double, long double, long double, long double)':
main.cpp:5:14: error: unable to find numeric literal operator 'operator""d'
#define INF (1d)2e9
^
main.cpp:51:17: note: in expansion of macro 'INF'
else return INF;
^~~
main.cpp:5:14: note: use -std=gnu++11 or -fext-numeric-literals to enable more built-in suffixes
#define INF (1d)2e9
^
main.cpp:51:17: note: in expansion of macro 'INF'
else return INF;
^~~
main.cpp:5:17: error: expected ';' before numeric constant
#define INF (1d)2e9
^
main.cpp:51:17: note: in expansion of macro 'INF'
else return INF;
^~~
main.cpp:51:20: warning: statement has no effect [-Wunused-value]
else return INF;
^
main.cpp: In function 'long double get_dist(const island&, const island&)':
main.cpp:5:14: error: unable to find numeric literal operator 'operator""d'
#define INF (1d)2e9
^
main.cpp:57:23: note: in expansion of macro 'INF'
ld val1,val2,minn=INF;
Non zero exit status: 1
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