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#include <fstream>
#define NMAX 200002
#define MMAX 400002
using namespace std;
ifstream fin("apm.in");
ofstream fout("apm.out");
struct Muchie
{int x, y, cost;
friend bool operator < (Muchie a, Muchie b);
friend bool operator > (Muchie a, Muchie b);
friend bool operator <= (Muchie a, Muchie b);
friend bool operator >= (Muchie a, Muchie b);
};
bool operator < (Muchie a, Muchie b)
{return a.cost<b.cost; }
bool operator > (Muchie a, Muchie b)
{return a.cost>b.cost; }
bool operator <= (Muchie a, Muchie b)
{return a.cost<=b.cost; }
bool operator >= (Muchie a, Muchie b)
{return a.cost>=b.cost; }
int n, m, nrsel, costtotal;
Muchie H[MMAX];
Muchie A[NMAX];
int tata[NMAX];
int h[NMAX]; ///h[i]=inaltimea arborelui cu radacina i
void creare();
void combinare(int n, Muchie H[], int poz);
Muchie extrageMin(int &n, Muchie H[]);
int Find (int x); ///returneaza radacina arborelui din care face parte x
void Union (int x, int y); ///reuneste arborele cu radacina x cu arborele cu radacina y
int main()
{Muchie mmin;
int cx, cy, i;
creare();
while (nrsel<n-1)
{
mmin=extrageMin(m, H);
cx=Find(mmin.x);
cy=Find(mmin.y);
if (cx!=cy)
{
nrsel++;
A[nrsel]=mmin;
costtotal+=mmin.cost;
Union(cx,cy);
}
}
//afisare
fout<<costtotal<<'\n';
fout<<n-1<<'\n';
for (i=1; i<n; i++)
fout<<A[i].x<<' '<<A[i].y<<'\n';
fout.close();
return 0;
}
void combinare(int n, Muchie H[], int poz)
{Muchie x=H[poz];
int fiu, tata;
tata=poz;
fiu=2*tata;
while (fiu<=n)
{
if (fiu+1<=n && H[fiu+1]<H[fiu]) fiu++;
if (x <= H[fiu]) break;
H[tata]=H[fiu];
tata=fiu;
fiu=2*tata;
}
H[tata]=x;
}
void creare()
{int i;
fin>>n>>m;
for (i=1; i<=m; i++) fin>>H[i].x>>H[i].y>>H[i].cost;
for (i=m/2; i>0; i--)
combinare(m, H, i);
}
Muchie extrageMin(int &n, Muchie H[])
{Muchie minim=H[1];
H[1]=H[n--];
combinare(n,H,1);
return minim;
}
int Find (int x)
///returneaza radacina arborelui din care face parte x
{int rad, aux;
rad=x;
while (tata[rad]) rad=tata[rad];
//compresia drumului
while (tata[x])
{
aux=tata[x];
tata[x]=rad;
x=aux;
}
return rad;
}
void Union (int x, int y) ///reuneste arborele cu radacina x cu arborele cu radacina y
{
if (h[x]<h[y]) tata[x]=y;
else
{tata[y]=x;
if (h[x]==h[y]) h[x]++;
}
///O(1)
}