Borderou de evaluare (job #2242500)
| Utilizator |  Pintea Teodor Stefan pinteastefan |
Data | 18 septembrie 2018 19:55:50 |
|---|---|---|---|
| Problema | Hashuri | Status | done |
| Runda | Arhiva educationala | Compilator | cpp | Vezi sursa |
| Scor | 0 | ||
Raport evaluator
Eroare de compilare:
user.cpp: In function ‘int main()’:
user.cpp:4:14: error: expected primary-expression before ‘=’ token
# define MOD = 666013;
^
user.cpp:14:19: note: in expansion of macro ‘MOD’
v[x % MOD] = 1;
^~~
user.cpp:4:22: error: expected ‘]’ before ‘;’ token
# define MOD = 666013;
^
user.cpp:14:19: note: in expansion of macro ‘MOD’
v[x % MOD] = 1;
^~~
user.cpp:14:22: error: expected primary-expression before ‘]’ token
v[x % MOD] = 1;
^
user.cpp:4:14: error: expected primary-expression before ‘=’ token
# define MOD = 666013;
^
user.cpp:16:34: note: in expansion of macro ‘MOD’
else if(op == 2 && v[x % MOD] == 1){
^~~
user.cpp:4:22: error: expected ‘]’ before ‘;’ token
# define MOD = 666013;
^
user.cpp:16:34: note: in expansion of macro ‘MOD’
else if(op == 2 && v[x % MOD] == 1){
^~~
user.cpp:4:22: error: expected ‘)’ before ‘;’ token
# define MOD = 666013;
^
user.cpp:16:34: note: in expansion of macro ‘MOD’
else if(op == 2 && v[x % MOD] == 1){
^~~
user.cpp:16:9: warning: this ‘else’ clause does not guard... [-Wmisleading-indentation]
else if(op == 2 && v[x % MOD] == 1){
^~~~
user.cpp:16:37: note: ...this statement, but the latter is misleadingly indented as if it is guarded by the ‘else’
else if(op == 2 && v[x % MOD] == 1){
^
user.cpp:16:37: error: expected primary-expression before ‘]’ token
user.cpp:19:9: error: ‘else’ without a previous ‘if’
else if( op == 3){
^~~~
user.cpp:4:14: error: expected primary-expression before ‘=’ token
# define MOD = 666013;
^
user.cpp:20:23: note: in expansion of macro ‘MOD’
if( v[x % MOD] == 1){
^~~
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