Borderou de evaluare (job #2241889)

Utilizator Iulia25Hosu Iulia Iulia25 Data 17 septembrie 2018 11:56:33
Problema Rascoala Status done
Runda Arhiva de probleme Compilator cpp | Vezi sursa
Scor 0

Raport evaluator

Eroare de compilare: user.cpp: In lambda function: user.cpp:15:40: warning: suggest parentheses around ‘&&’ within ‘||’ [-Wparentheses] return !(a.ac < b.ac || a.ac == b.ac && a.init < b.init || ~~~~~~~~~~~~~^~~~~~~~~~~~~~~~~~ user.cpp:16:45: warning: suggest parentheses around ‘&&’ within ‘||’ [-Wparentheses] a.ac == b.ac && a.init == b.init && a.poz < b.poz); ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~^~~~~~~~~~~~~~~~ user.cpp: In function ‘int main()’: user.cpp:39:45: error: no matching function for call to ‘max(int, const long long int&)’ int x = max(1, min(k, q.top().ac - a.ac)); ^ In file included from /usr/include/c++/6/bits/char_traits.h:39:0, from /usr/include/c++/6/ios:40, from /usr/include/c++/6/istream:38, from /usr/include/c++/6/fstream:38, from user.cpp:1: /usr/include/c++/6/bits/stl_algobase.h:219:5: note: candidate: template<class _Tp> constexpr const _Tp& std::max(const _Tp&, const _Tp&) max(const _Tp& __a, const _Tp& __b) ^~~ /usr/include/c++/6/bits/stl_algobase.h:219:5: note: template argument deduction/substitution failed: user.cpp:39:45: note: deduced conflicting types for parameter ‘const _Tp’ (‘int’ and ‘long long int’) int x = max(1, min(k, q.top().ac - a.ac)); ^ In file included from /usr/include/c++/6/bits/char_traits.h:39:0, from /usr/include/c++/6/ios:40, from /usr/include/c++/6/istream:38, from /usr/include/c++/6/fstream:38, from user.cpp:1: /usr/include/c++/6/bits/stl_algobase.h:265:5: note: candidate: template<class _Tp, class _Compare> constexpr const _Tp& std::max(const _Tp&, const _Tp&, _Compare) max(const _Tp& __a, const _Tp& __b, _Compare __comp) ^~~ /usr/include/c++/6/bits/stl_algobase.h:265:5: note: template argument deduction/substitution failed: user.cpp:39:45: note: deduced conflicting types for parameter ‘const _Tp’ (‘int’ and ‘long long int’) int x = max(1, min(k, q.top().ac - a.ac)); ^

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