Cod sursa(job #2225796)

Utilizator MiricaMateiMirica Matei MiricaMatei Data 28 iulie 2018 12:08:29
Problema Curcubeu Scor 0
Compilator cpp Status done
Runda Arhiva de probleme Marime 2.29 kb
#include <cstdio>
#include <algorithm>

using namespace std;

int a[1000005], b[1000005], c[1000005];
int t[1000005], nxt[1000005];
int ans[1000005];

inline int f(int x) {
  int y = x;
  while (x != t[x])
    x = t[x];
  while (y != t[y]) {
    int aux = t[y];
    t[y] = x;
    y = aux;
  }
  return x;
}

inline void u(int x, int y) {
  x = f(x);
  y = f(y);
  if (x == y)
    return ;
  t[y] = x;
  nxt[x] = max(nxt[x], nxt[y]);
}

int get(int x) {
  return nxt[f(x)];
}

class OutParser {
private:
  FILE *fout;
  char *buff;
  int sp;

  void write_ch(char ch) {
    if (sp == 50000) {
      fwrite(buff, 1, 50000, fout);
      sp = 0;
      buff[sp++] = ch;
    } else {
      buff[sp++] = ch;
    }
  }


public:
  OutParser(const char* name) {
    fout = fopen(name, "w");
    buff = new char[50000]();
    sp = 0;
  }
  ~OutParser() {
    fwrite(buff, 1, sp, fout);
    fclose(fout);
  }

  OutParser& operator << (int vu32) {
    if (vu32 <= 9) {
      write_ch(vu32 + '0');
    } else {
      (*this) << (vu32 / 10);
      write_ch(vu32 % 10 + '0');
    }
    return *this;
  }

  OutParser& operator << (long long vu64) {
    if (vu64 <= 9) {
      write_ch(vu64 + '0');
    } else {
      (*this) << (vu64 / 10);
      write_ch(vu64 % 10 + '0');
    }
    return *this;
  }

  OutParser& operator << (char ch) {
    write_ch(ch);
    return *this;
  }
  OutParser& operator << (const char *ch) {
    while (*ch) {
      write_ch(*ch);
      ++ch;
    }
    return *this;
  }
};

int main() {
  freopen("curcubeu.in", "r", stdin);
  OutParser out("curcubeu.in");

  int n, x, y;
  scanf("%d", &n);
  scanf("%d%d%d", &a[1], &b[1], &c[1]);
  t[1] = 1;
  nxt[1] = 2;
  for (int i = 2; i < n; ++i) {
    a[i] = 1LL * a[i - 1] * i % n;
    b[i] = 1LL * b[i - 1] * i % n;
    c[i] = 1LL * c[i - 1] * i % n;
    t[i] = i;
    nxt[i] = i + 1;
  }
  for (int i = n - 1; i >= 1; --i) {
    x = min(a[i], b[i]);
    y = a[i] ^ b[i] ^ x;
    if (ans[x] != 0)
      x = get(x);
    for (int j = x; j <= y; j = get(j)) {
      ans[j] = c[i];
      if (ans[j - 1] != 0)
        u(j - 1, j);
      if (ans[j + 1] != 0)
        u(j + 1, j);
    }
  }

  for (int i = 1; i < n; ++i)
    out << ans[i] << '\n';

  return 0;
}