Compilare: user.cpp: In function ‘int main()’: user.cpp:42:46: warning: array subscript has type ‘char’ [-Wchar-subscripts] if ( j == str[0]) ap[ j ][0] = 1; else ap[ j ][0] = 0; ^ user.cpp:42:73: warning: array subscript has type ‘char’ [-Wchar-subscripts] if ( j == str[0]) ap[ j ][0] = 1; else ap[ j ][0] = 0; ^ user.cpp:43:46: warning: array subscript has type ‘char’ [-Wchar-subscripts] if (invChr(j) == str[0]) ap[invChr(j)][0] = 1; else ap[invChr(j)][0] = 0; ^ user.cpp:43:73: warning: array subscript has type ‘char’ [-Wchar-subscripts] if (invChr(j) == str[0]) ap[invChr(j)][0] = 1; else ap[invChr(j)][0] = 0; ^ user.cpp:48:25: warning: array subscript has type ‘char’ [-Wchar-subscripts] ap[ j ][i] = ap[ j ][i - 1]; ^ user.cpp:48:44: warning: array subscript has type ‘char’ [-Wchar-subscripts] ap[ j ][i] = ap[ j ][i - 1]; ^ user.cpp:49:25: warning: array subscript has type ‘char’ [-Wchar-subscripts] ap[invChr(j)][i] = ap[invChr(j)][i - 1]; ^ user.cpp:49:44: warning: array subscript has type ‘char’ [-Wchar-subscripts] ap[invChr(j)][i] = ap[invChr(j)][i - 1]; ^ user.cpp:51:18: warning: array subscript has type ‘char’ [-Wchar-subscripts] ap[str[i]][i]++; ^ user.cpp:66:35: warning: array subscript has type ‘char’ [-Wchar-subscripts] sol2 = nDiv / 2 * (ap[sol1][k - 1] + ap[invChr(sol1)][k - 1]); ^ user.cpp:66:61: warning: array subscript has type ‘char’ [-Wchar-subscripts] sol2 = nDiv / 2 * (ap[sol1][k - 1] + ap[invChr(sol1)][k - 1]); ^ user.cpp:69:40: warning: array subscript has type ‘char’ [-Wchar-subscripts] sol2 += ap[invChr(sol1)][k - 1]; ^ user.cpp:71:40: warning: array subscript has type ‘char’ [-Wchar-subscripts] sol2 += ap[ sol1 ][k - 1]; ^ user.cpp:75:36: warning: array subscript has type ‘char’ [-Wchar-subscripts] sol2 += ap[invChr(sol1)][nMod]; ^ user.cpp:77:36: warning: array subscript has type ‘char’ [-Wchar-subscripts] sol2 += ap[ sol1 ][nMod]; ^