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// https://goo.gl/fBmFxu
#include <bits/stdc++.h>
using namespace std;
#define NMAX 100009
#define LGMAX 21
#define MMAX 200009
#define kInf (1 << 30)
#define kInfLL (1LL << 60)
#define kMod 666013
#define edge pair<int, int>
#define x first
#define y second
#define USE_FILES "MLC"
#ifdef USE_FILES
#define cin fin
#define cout fout
ifstream fin("rmq.in");
ofstream fout("rmq.out");
#endif
// number of tests from "in"
int test_cnt = 1;
void clean_test();
// your global variables are here
// Binary Indexed Trees
template<typename T = int>
struct RMQ {
int size;
T& (*func)(T&, T&);
vector<T> lg;
vector<vector<T>> rmq;
RMQ(int _size, vector<T> &v, T& (*_func)(T&, T&)) :
size(_size),
func(_func),
lg(size + 1),
rmq(LGMAX, vector<T>(size + 1)) {
int n = size;
lg[0] = lg[1] = 0;
for (int i = 2; i <= n; ++i) {
lg[i] = lg[i / 2] + 1;
}
for (int i = 1; i <= n; ++i) {
rmq[0][i] = v[i];
}
for (int k = 1; (1LL << k) <= n; ++k) {
for (int i = 1; i <= n - (1 << k) + 1; ++i) {
rmq[k][i] = func(rmq[k - 1][i], rmq[k - 1][i + (1 << (k - 1))]);
}
}
}
T query(int i, int j) {
if (i > j) {
swap(i, j);
}
int k = lg[j - i + 1];
return func(rmq[k][i], rmq[k][j - (1 << k) + 1]);
}
};
int& func_min(int &a, int &b) {
return a <= b ? a : b;
}
int& func_max(int &a, int &b) {
return a >= b ? a : b;
}
// your solution is here
void solve() {
int n, Q;
cin >> n >> Q;
// RMQ<int> aint(n + 1, func_min, numeric_limits<int>::max());
vector<int> v(n + 1);
for (int i = 1; i <= n; ++i) {
cin >> v[i];
}
RMQ<int> rmq(n, v, func_min);
while (Q--) {
int start, end;
cin >> start >> end;
cout << rmq.query(start, end) << "\n";
}
if (test_cnt > 0) {
clean_test();
}
}
void clean_test() {
// clean if needed
}
int main() {
// cin >> test_cnt;
while (test_cnt--) {
solve();
}
return 0;
}