#include <fstream>
#include <vector>
#include <algorithm>
#include <cstring>
using namespace std;
const unsigned long long kMod = 666013;
class input{
public:
int x,y,z,a,b,c,n;
input(int x, int y, int z, int a, int b, int c, int n) :
x(x), y(y), z(z), a(a), b(b), c(c), n(n) {}
};
class Task {
public:
void solve() {
read_input();
print_output(get_result());
}
private:
int n;
vector<input*> v;
void read_input() {
ifstream fin("iepuri.in");
fin >> n;
for (int i = 0, x,y,z,a,b,c,days; i < n; i++) {
fin >> x >> y >> z >> a >> b >> c >> days;
auto *input1 = new input(x, y, z, a, b, c, days);
v.push_back(input1);
}
fin.close();
}
#define KMAX 3
void multiply_matrix2(int A[KMAX][KMAX], int B[KMAX], int C[KMAX]) {
int tmp[KMAX];
// tmp = A * B
for (int i = 0; i < KMAX; ++i) {
for (int j = 0; j < KMAX; ++j) {
unsigned long long sum = 0; // presupun ca suma incape pe 64 de biti
for (int k = 0; k < KMAX; ++k) {
sum += 1LL * A[i][k] * B[k];
}
tmp[i] = sum % kMod;
}
}
// C = tmp
memcpy(C, tmp, sizeof(tmp));
}
void multiply_matrix(int A[KMAX][KMAX], int B[KMAX][KMAX], int C[KMAX][KMAX]) {
int tmp[KMAX][KMAX];
// tmp = A * B
for (int i = 0; i < KMAX; ++i) {
for (int j = 0; j < KMAX; ++j) {
unsigned long long sum = 0; // presupun ca suma incape pe 64 de biti
for (int k = 0; k < KMAX; ++k) {
sum += 1LL * A[i][k] * B[k][j];
}
tmp[i][j] = sum % kMod;
}
}
// C = tmp
memcpy(C, tmp, sizeof(tmp));
}
void power_matrix(int C[KMAX][KMAX], int p, int R[KMAX][KMAX]) {
int tmp[KMAX][KMAX];
for (int i = 0; i < KMAX; ++i) {
for (int j = 0; j < KMAX; ++j) {
tmp[i][j] = (i == j) ? 1 : 0;
}
}
while (p != 1) {
if (p % 2 == 0) {
multiply_matrix(C, C, C); // C = C*C
p /= 2; // ramane de calculat C^(p/2)
} else {
// reduc la cazul anterior:
multiply_matrix(tmp, C, tmp); // tmp = tmp*C
--p; // ramane de calculat C^(p-1)
}
}
// avem o parte din rezultat in C si o parte in tmp
multiply_matrix(C, tmp, R); // rezultat = tmp * C
}
vector<int> get_result() {
vector<int> result;
for(auto i : v){//for each input
int C[3][3] = {
{i->a, i->b, i->c},
{1, 0 ,0},
{0, 1, 0},
};
int d[3] = {i->z, i->y, i->x};
power_matrix(C, i->n ,C);
multiply_matrix2(C,d,d);
result.push_back(d[2]);
}
return result;
}
void print_output(vector<int> result) {
ofstream fout("iepuri.out");
for (auto i : result)
fout << i << "\n";
fout.close();
}
};
int main() {
Task task;
task.solve();
return 0;
}