Pagini recente » Cod sursa (job #1558370) | Cod sursa (job #2965682) | Cod sursa (job #679876) | Cod sursa (job #2268322) | Cod sursa (job #2150067)
#include <iostream>
#include <fstream>
#include <string.h>
#define MOD 666013
using namespace std;
ifstream fin("kfib.in");
ofstream fout("kfib.out");
int a[2][2] = {
{0, 1},
{1, 1}
};
int ret[2][2] = {
{1, 0},
{0, 1}
};
int n, c[2][2];
inline void matmult(int a[2][2], int b[2][2], int c[2][2])
{
for(int i = 0; i < 2; i++)
for(int j = 0; j < 2; j++)
{
c[i][j] = 0;
for(int k = 0; k < 2; k++)
c[i][j] =(c[i][j] + (1LL * a[i][k] * b[k][j]) % MOD) % MOD;
}
}
inline int fib_lgput(int n) // ridicam matricea constanta a la puterea n-1 si obtinem al n-ulea termen al sirului lui fib
{
n--;
while(n)
{
if(n % 2 == 1)
{
matmult(a, ret, c);
memcpy(ret, c, sizeof(ret));
}
matmult(a, a, c);
memcpy(a, c, sizeof(a));
n /= 2;
}
return ret[1][1];
}
int main()
{
fin >> n;
fout << fib_lgput(n);
return 0;
}