Pagini recente » Diferente pentru teorema-chineza-a-resturilor intre reviziile 36 si 35 | Cod sursa (job #2234414) | Cod sursa (job #280053) | Monitorul de evaluare | Cod sursa (job #2128043)
#include "stdio.h"
#define MAX_N 100000
/* IO */
FILE *fin;
FILE *fout;
/* Problem Data */
int N;
int array[MAX_N];
int best[MAX_N];
int predecesor[MAX_N];
int max_index;
void read(void) {
fin = fopen("scmax.in", "r");
fscanf(fin, "%d", &N);
int i;
for (i = 0; i < N; i++) {
fscanf(fin, "%d", &array[i]);
}
fclose(fin);
}
void write(void) {
int subsequence[best[max_index]];
int index = max_index, nr = 0, i;
subsequence[nr++] = array[index];
while (predecesor[index] >= 0) {
subsequence[nr++] = array[predecesor[index]];
index = predecesor[index];
}
fout = fopen("scmax.out", "w");
fprintf(fout, "%d\n", best[max_index]);
for (i = nr - 1; i >= 0; i--) {
fprintf(fout, "%d ", subsequence[i]);
}
fclose(fout);
}
void solve(void) {
int i, j, max_best, global_best = 0;
best[0] = 1;
predecesor[0] = -1;
for (i = 1; i < N; i++) {
predecesor[i] = -1;
max_best = 0;
for (j = i - 1; j >= 0; j--) {
if (array[i] > array[j]) {
if (best[j] > max_best) {
max_best = best[j];
predecesor[i] = j;
}
}
}
best[i] = 1 + max_best;
if (best[i] > global_best) {
global_best = best[i];
max_index = i;
}
}
}
int main(void) {
read();
solve();
write();
return 0;
}