#include <fstream>
#include <algorithm>
#define DIM 100005
#define MOD 666013
using namespace std;
class InParser {
private:
FILE *fin;
char *buff;
int sp;
char read_ch() {
++sp;
if (sp == 4096) {
sp = 0;
fread(buff, 1, 4096, fin);
}
return buff[sp];
}
public:
InParser(const char* nume) {
fin = fopen(nume, "r");
buff = new char[4096]();
sp = 4095;
}
InParser& operator >> (int &n) {
char c;
while (!isdigit(c = read_ch()) && c != '-');
int sgn = 1;
if (c == '-') {
n = 0;
sgn = -1;
} else {
n = c - '0';
}
while (isdigit(c = read_ch())) {
n = 10 * n + c - '0';
}
n *= sgn;
return *this;
}
InParser& operator >> (long long &n) {
char c;
n = 0;
while (!isdigit(c = read_ch()) && c != '-');
long long sgn = 1;
if (c == '-') {
n = 0;
sgn = -1;
} else {
n = c - '0';
}
while (isdigit(c = read_ch())) {
n = 10 * n + c - '0';
}
n *= sgn;
return *this;
}
} f("distincte.in");
ofstream g("distincte.out");
int n, m, k, aint[4 * DIM], s, v[DIM], poz[DIM], sol[DIM];
void update(int nod, int st, int dr, int poz, int val){
if(st == dr && st == poz){
aint[nod] = val;
return;
}
int mid = (st + dr) / 2;
if(poz <= mid)
update(2 * nod, st, mid, poz, val);
else
update(2 * nod + 1, mid + 1, dr, poz, val);
aint[nod] = (aint[2 * nod] + aint[2 * nod + 1]) % MOD;
}
void query(int nod, int st, int dr, int a, int b){
if(a <= st && b >= dr){
s += aint[nod];
s %= MOD;
return;
}
int mid = (st + dr) / 2;
if(a <= mid)
query(2 * nod, st, mid, a, b);
if(b > mid)
query(2 * nod + 1, mid + 1, dr, a, b);
}
struct quer{
int x, y, init;
}q[DIM];
bool cmp(quer a, quer b){
if(a.y == b.y)
return a.x < b.x;
return a.y < b.y;
}
int main()
{
f>>n>>k>>m;
for(int i = 1; i <= n; ++ i)
f>>v[i];
for(int i = 1; i <= m; ++ i){
f>>q[i].x>>q[i].y;
q[i].init = i;
}
sort(q + 1, q + m + 1, cmp);
int cnt = 1;
for(int i = 1; i <= m; ++ i){
int N = q[i].y;
for(; cnt <= q[i].y; ++cnt){
if(!poz[v[cnt]])
update(1, 1, n, cnt, v[cnt]);
else{
update(1, 1, n, poz[v[cnt]], 0);
update(1, 1, n, cnt, v[cnt]);
}
poz[v[cnt]] = cnt;
}
s = 0;
query(1, 1, n, q[i].x, q[i].y);
sol[q[i].init] = s;
}
for(int i = 1; i <= m; ++ i)
g<<sol[i]<<"\n";
return 0;
}