Cod sursa(job #1815656)
| Utilizator | Data | 25 noiembrie 2016 16:42:57 | |
|---|---|---|---|
| Problema | Ridicare la putere in timp logaritmic | Scor | 10 |
| Compilator | cpp | Status | done |
| Runda | Arhiva educationala | Marime | 0.49 kb |
#include <cstdio>
using namespace std;
const int MOD = 1999999973;
long long mypow(long long n, int p) {
long long ans;
ans = 1;
for( ; p; p = (p >> 1)) {
if(p & 1)
ans = (ans * n) % MOD;
n = n * n;
}
return ans;
}
int main() {
freopen("lgput.in", "r", stdin);
freopen("lgput.out", "w", stdout);
long long n;
int p;
scanf("%lld%d", &n, &p);
printf("%lld", mypow(n, p));
return 0;
}
