Cod sursa(job #1789731)
Utilizator | Florentin Dumitru deivid | Data | 27 octombrie 2016 14:56:45 |
---|---|---|---|
Problema | Ridicare la putere in timp logaritmic | Scor | 100 |
Compilator | cpp | Status | done |
Runda | Arhiva educationala | Marime | 0.43 kb |
#include <stdio.h>
long long lgpow(long long a, long long b, long long mod) {
long long s = 1, p = a;
b %= (mod - 1);
while (b) {
if (b & 1) {
s = (s * p) % mod;
}
p = (p * p) % mod;
b >>= 1;
}
return s;
}
int main() {
freopen("lgput.in", "r", stdin);
freopen("lgput.out", "w", stdout);
long long a, b;
scanf("%lld %lld", &a, &b);
printf("%lld\n", lgpow(a, b, 1999999973));
return 0;
}