Cod sursa(job #1784593)
Utilizator | Data | 20 octombrie 2016 11:34:17 | |
---|---|---|---|
Problema | Ridicare la putere in timp logaritmic | Scor | 10 |
Compilator | cpp | Status | done |
Runda | Arhiva educationala | Marime | 0.41 kb |
#include <iostream>
#include <stdio.h>
using namespace std;
int PowR(int a, int b) {
if (b == 0) return 1;
if (b == 1) return a;
if (b % 2) return a * PowR(a, b - 1);
else return PowR(a, b/2) * PowR(a, b/2);
}
int main() { //metoda "optimizata" yupi
freopen("lgput.in", "r", stdin);
freopen("lgput.out", "w", stdout);
int a,b;
cin >> a >> b;
cout << PowR(a,b);
}