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/*#include <iostream>
#include <cstdio>
#include <cmath>
#include <vector>
#include <algorithm>
using namespace std;
#define MOD1 100007
#define MOD2 100021
void strmatch(string A, string B){
vector<int> v;
int p = 26, p1 = 1, p2 = 1;
int hashA1 = 0, hashB1 = 0, hashA2 = 0, hashB2 = 0;
int sizeA = A.size(), sizeB = B.size();
for(int i = 0; i < sizeA; ++i){
hashA1 = (hashA1 * p + A[i]) % MOD1;
hashB1 = (hashB1 * p + B[i]) % MOD1;
hashA2 = (hashA2 * p + A[i]) % MOD2;
hashB2 = (hashB2 * p + B[i]) % MOD2;
if(i != 0){
p1 = (p1 * p) % MOD1;
p2 = (p2 * p) % MOD2;
}
}
if(hashA1 == hashB1 && hashA2 == hashB2){
v.push_back(0);
}
for(int i = sizeA; i < sizeB; ++i){
hashB1 = ((hashB1 - (B[i-sizeA] * p1) % MOD1 + MOD1) * p + B[i]) % MOD1;
hashB2 = ((hashB2 - (B[i-sizeA] * p2) % MOD2 + MOD2) * p + B[i]) % MOD2;
/*if (hashB1 < 0) {
hashB1 += MOD1;
}
if (hashB2 < 0) {
hashB2 += MOD2;
}
if(hashB1 == hashA1 && hashB2 == hashA2){
v.push_back(i-sizeA+1);
}
}
cout << v.size() << endl;
int minSize = min((int)v.size(), 1000);
for(int i = 0; i < minSize; ++i)
cout << v[i] << " ";
}
int main(){
freopen("strmatch.in", "r", stdin);
freopen("strmatch.out","w", stdout);
string A, B;
cin >> A >> B;
strmatch(A, B);
return 0;
}*/
#include <stdio.h>
#include <string.h>
#define MAXN 2000001
#define P 73
#define MOD1 100007
#define MOD2 100021
char A[MAXN], B[MAXN];
int NA, NB;
int hashA1, hashA2, P1, P2;
char match[MAXN];
int main()
{
freopen("strmatch.in", "rt", stdin);
freopen("strmatch.out", "wt", stdout);
scanf("%s %s", A, B);
NA = strlen(A);
NB = strlen(B);
P1 = P2 = 1;
hashA1 = hashA2 = 0;
for (int i = 0; i < NA; i++)
{
hashA1 = (hashA1 * P + A[i]) % MOD1;
hashA2 = (hashA2 * P + A[i]) % MOD2;
if (i != 0)
P1 = (P1 * P) % MOD1,
P2 = (P2 * P) % MOD2;
}
if (NA > NB)
{
printf("0\n");
return 0;
}
int hash1 = 0, hash2 = 0;
for (int i = 0; i < NA; i++)
hash1 = (hash1 * P + B[i]) % MOD1,
hash2 = (hash2 * P + B[i]) % MOD2;
int Nr = 0;
if (hash1 == hashA1 && hash2 == hashA2)
match[0] = 1, Nr++;
for (int i = NA; i < NB; i++)
{
hash1 = ((hash1 - (B[i - NA] * P1) % MOD1 + MOD1) * P + B[i]) % MOD1;
hash2 = ((hash2 - (B[i - NA] * P2) % MOD2 + MOD2) * P + B[i]) % MOD2;
if (hash1 == hashA1 && hash2 == hashA2)
match[ i - NA + 1 ] = 1, Nr++;
}
printf("%d\n", Nr);
Nr = 0;
for (int i = 0; i < NB && Nr < 1000; i++)
if (match[i])
Nr++,
printf("%d ", i);
printf("\n");
return 0;
}