Cod sursa(job #1775746)

Utilizator ajeccAjechiloae Eugen ajecc Data 10 octombrie 2016 17:59:04
Problema Ridicare la putere in timp logaritmic Scor 10
Compilator cpp Status done
Runda Arhiva educationala Marime 1.83 kb
#include <bits/stdc++.h>
#define for0(i,n) for(int i=0; i<n; i++)
#define for1(i,n) for(int i=1; i<=n; i++)
#define pb push_back
#define mp make_pair
#define all(v) v.begin(), v.end()
#define V vector<int>
#define VP vector<pair<int, int> >
#define clr(A,x) memset(A, x, sizeof(A))
#define cpy(A,B) memcpy(A, B, sizeof(B))
#define g(s) getline(cin, s) ///ai grija la fin/cin ///
#define FASTIO ios_base::sync_with_stdio(0)
const long long INFLL = (1LL<<62);
const int INFINT = 2000000000;
typedef long long ll;
typedef unsigned long long ull;
using namespace std;
/*template <typename T>
string to_string(const T& n){
    ostringstream os;
    os << n;
    return os.str();
}
*/

/*struct coord
{
    int x,y;

};
bool operator<(const coord &l, const coord &r)
{
    return (l.x<r.x || (l.x==r.x && l.y<r.y));
}*/

/*void invers_modular(int a, int b, int& d, int& x, int & y)
{
    if(!b)
    {
        d=a;
        x=1;
        y=0;
        return ;
    }2
    int x0, y0;
    invers_modular(b, a%b, d, x0, y0);
    x=y0;
    y=x0-a/b*y0;
} // daca x<0 se aduna cu mod pana e mai mare, x fiind rezultatul*/

/*ull p(int baze, int exponent)
{
    if(exponent==0)
        return 1;

    if(exponent%2==0)
        return p(baze*baze, exponent/2);
    else return baze*p(baze, exponent-1);
}*/
ifstream fin("lgput.in"); /// modifica cu numele corespunzator
ofstream fout("lgput.out"); /// modifica cu numele corespunzator

ull baza, exponent;
const ull MOD = 1999999973;

ull putere(ull baza, ull exponent)
{
    if(exponent == 0)
        return 1;
    if(exponent % 2 == 0) return putere(baza * baza, exponent / 2) % MOD;
    return ((baza % MOD) * (putere(baza, exponent - 1) % MOD) % MOD);
}


int main()
{
    fin>>baza>>exponent;
    fout<<putere(baza, exponent);



    return 0;
}