Cod sursa(job #1768922)

Utilizator cristina_borzaCristina Borza cristina_borza Data 1 octombrie 2016 18:17:02
Problema Oite Scor 60
Compilator cpp Status done
Runda Arhiva de probleme Marime 2.29 kb
#include <fstream>
#include <map>

using namespace std;

class InParser {
private:
    FILE *fin;
    char *buff;
    int sp;

    char read_ch() {
        ++sp;
        if (sp == 4096) {
            sp = 0;
            fread(buff, 1, 4096, fin);
        }
        return buff[sp];
    }

public:
    InParser(const char* nume) {
        fin = fopen(nume, "r");
        buff = new char[4096]();
        sp = 4095;
    }

    InParser& operator >> (int &n) {
        char c;
        while (!isdigit(c = read_ch()) && c != '-');
        int sgn = 1;
        if (c == '-') {
            n = 0;
            sgn = -1;
        } else {
            n = c - '0';
        }
        while (isdigit(c = read_ch())) {
            n = 10 * n + c - '0';
        }
        n *= sgn;
        return *this;
    }
} f ("oite.in");

class OutParser {
private:
    FILE *fout;
    char *buff;
    int sp;

    void write_ch(char ch) {
        if (sp == 50000) {
            fwrite(buff, 1, 50000, fout);
            sp = 0;
            buff[sp++] = ch;
        } else {
            buff[sp++] = ch;
        }
    }


public:
    OutParser(const char* name) {
        fout = fopen(name, "w");
        buff = new char[50000]();
        sp = 0;
    }
    ~OutParser() {
        fwrite(buff, 1, sp, fout);
        fclose(fout);
    }

    OutParser& operator << (int vu32) {
        if (vu32 <= 9) {
            write_ch(vu32 + '0');
        } else {
            (*this) << (vu32 / 10);
            write_ch(vu32 % 10 + '0');
        }
        return *this;
    }

    OutParser& operator << (char ch) {
        write_ch(ch);
        return *this;
    }
    OutParser& operator << (const char *ch) {
        while (*ch) {
            write_ch(*ch);
            ++ch;
        }
        return *this;
    }
} g ("oite.out");

int n , l , ans;
int v[1500];

map <int , int> mp;

int main() {
    f >> n >> l;
    for (int i = 1; i <= n; ++i) {
        f >> v[i];
    }

    for (int i = 1; i < n; ++i) {
        for (int j = i + 1; j <= n; ++j) {
            if (v[i] + v[j] <= l)
                ans += mp[l - v[i] - v[j]];
        }

        for (int j = 1; j < i; ++j) {
            ++mp[v[i] + v[j]];
        }
    }

    g << ans;
    return 0;
}