#include <bits/stdc++.h>
#define for0(i,n) for(int i=0; i<n; i++)
#define for1(i,n) for(int i=1; i<=n; i++)
#define pb push_back
#define mp make_pair
#define all(v) v.begin(), v.end()
#define V vector<int>
#define VP vector<pair<int, int> >
#define clr(A,x) memset(A, x, sizeof(A))
#define cpy(A,B) memcpy(A, B, sizeof(B))
#define g(s) getline(cin, s) ///ai grija la fin/cin ///
#define FASTIO ios_base::sync_with_stdio(0)
const long long INFLL = (1LL<<62);
const int INFINT = 2000000000;
typedef long long ll;
typedef unsigned long long ull;
using namespace std;
/*template <typename T>
string to_string(const T& n){
    ostringstream os;
    os << n;
    return os.str();
}
*/

/*struct coord
{
    int x,y;

};
bool operator<(const coord &l, const coord &r)
{
    return (l.x<r.x || (l.x==r.x && l.y<r.y));
}*/

/*void invers_modular(int a, int b, int& d, int& x, int & y)
{
    if(!b)
    {
        d=a;
        x=1;
        y=0;
        return ;
    }2
    int x0, y0;
    invers_modular(b, a%b, d, x0, y0);
    x=y0;
    y=x0-a/b*y0;
} // daca x<0 se aduna cu mod pana e mai mare, x fiind rezultatul*/

/*ull p(int baze, int exponent)
{
    if(exponent==0)
        return 1;

    if(exponent%2==0)
        return p(baze*baze, exponent/2);
    else return baze*p(baze, exponent-1);
}*/
ifstream fin("cautbin.in"); /// modifica cu numele corespunzator
ofstream fout("cautbin.out"); /// modifica cu numele corespunzator
int v[100002];
int n, m;

int cer0(int x)
{
    int l = 1, r = n, mid;
    bool gasit = 0;
    while(l < r)
    {
        mid = (l + r) / 2;
        if(v[mid] == x)
        {
            gasit = 1;
            break;
        }
        if(v[mid] < x)
            l = mid + 1;
        else r = mid;
    }
    mid = (l + r) / 2;
    if(!gasit)
        return -1;
    while(v[mid] == x)
        mid++;
    return mid - 1;
}

int cer1(int x)
{
    int l = 1, r = n, mid;
    while(l < r)
    {
        mid = (l + r) / 2;
        if(v[mid] <= x)
            l = mid + 1;
        else r = mid;
    }
    mid = (l + r) / 2;
    if(v[mid] > x)
        mid--;
    return mid;
}

int cer2(int x)
{
    int l = 1, r = n, mid;
    while(l < r)
    {
        mid = (l + r) / 2;
        if(v[mid] < x)
            l = mid + 1;
        else r = mid;
    }
    mid = (l + r) / 2;
    if(v[mid] < x)
        mid++;
    return mid;
}

int main()
{
    fin>>n;
    for1(i, n)
        fin>>v[i];
    fin>>m;
    for1(nrquery, m)
    {
        int q, x;
        fin>>q>>x;
        if(q == 0)
            fout<<cer0(x)<<'\n';
        else if(q == 1)
            fout<<cer1(x)<<'\n';
        else if(q == 2)
            fout<<cer2(x)<<'\n';

    }




    return 0;
}