Cod sursa(job #1709992)

Utilizator UBB_Muresan_Nasca_StefanUBB Muresan Nasca Stefan UBB_Muresan_Nasca_Stefan Data 28 mai 2016 14:43:08
Problema Consecutive Scor 0
Compilator cpp Status done
Runda ONIS 2016 - Runda - 2 - ACM ICPC Romanian Programming Contest Marime 2.19 kb
#include <fstream>
#include <cmath>
#include <vector>
#include <utility>
#include <algorithm>
using namespace std;

long long n,m,i,j,t,e,sum,k;

bool CMP(pair<long long,long long> T1, pair<long,long> T2)
{
    return T1.second - T1.first < T2.second - T2.first;
}

vector< pair<long long , long long> > a;
vector< pair<long long, long long> > b;
int main()
{

    ifstream fin("consecutive.in");
    ofstream fout("consecutive.out");
    fin>>t;
    for(e=1;e<=t;e++)
    {
        a.clear(); b.clear();
        int contor = 2;
        fin>>n;
        //int an = sqrt(n);
        int an = (-1 +  sqrt(1+8*n))/2;
        j=n/contor;
        //for(i=n/contor + 1;i>=1;i--)
        while(j>=1)
        {
            //fout<<i<<"\n";

            for(i=j + contor / 2 - 1; i < j + contor / 2 + 2;i++)
            {
                sum = (i * (i + 1) / 2 - n) * 2;
                k = (-1 + sqrt(1+4*sum))/2;
                if(((i*(i+1)/2 - k*(k+1)/2) == n) && (i>0))
                {
                    if(i != k + 1)
                    {
                        a.push_back({k+1,i});
                    }
                }
            }

            contor++;
            j=n/contor;
            //fout<<contor<<"\n";
            if (j < an-3 && contor > 52500)break;
            //if(j < an) break;
            //fout<<j<<" "<<contor<<"\n";
        }

        /*for (i = 1; i < j; i++){
            sum = (i * (i + 1) / 2 - n) * 2;
                k = (-1 + sqrt(1+4*sum))/2;
                if(((i*(i+1)/2 - k*(k+1)/2) == n) && (i>0))
                {
                    if(i != k + 1)
                    {
                        a.push_back({k+1,i});
                    }
                }
        } */

        sort(a.begin(), a.end(), CMP);
        for (i = 0; i < a.size(); i++){
            if (i == 0){
                b.push_back(a[i]);
            } else {
                if (a[i] != a[i - 1]){
                    b.push_back(a[i]);
                }
            }
        }

        fout<<b.size()<<"\n";
        for(i=0;i<b.size();++i)
        {
            fout<<b[i].first<<" "<<b[i].second<<"\n";
        }
    }
    return 0;
}