Pagini recente » Cod sursa (job #2574137) | Cod sursa (job #1695544) | Cod sursa (job #574295) | Cod sursa (job #2365840) | Cod sursa (job #1609717)
#include <cstdio>
using namespace std;
const int NMAX = 500000;
int v[NMAX + 5];
int ap[NMAX + 5];
int main()
{
freopen("divk.in", "r", stdin);
freopen("divk.out", "w", stdout);
int n, t, d, a, b, k;
long long s = 0;
scanf("%d %d %d %d", &n, &k, &a, &b);
for(register int i = 1; i <= n; ++i )
{
scanf("%d", &t);
v[i] = ( v[i - 1] + t ) % k; /// practic suma de la 1 la i (restul)
if( i >= a )
++ap[v[i - a]]; /// crestem de cate ori a aparut restul
if( i > b )
--ap[v[i - b - 1]]; /// scadem pt ca l > b;
s += ap[v[i]];
}
printf("%lld", s);
return 0;
}