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#include <iostream>
#include <fstream>
using namespace std;
int main()
{
//Dandu-se T perechi de numere naturale (a, b), sa se calculeze cel mai mare divizor comun al numerelor din fiecare pereche in parte.
int a, b, cmmdc, n;
ifstream fin;
fin.open ("euclid2.in");
ofstream fout;
fout.open ("euclid2.out");
fin>>n>>a>>b;
for (int i=0; i<=n; i++)
{
while (b>0)
{
cmmdc=a%b;
a=b;
b=cmmdc;
}
fout<<a;
fin>>a>>b;
}
/*
//Sa se determine subsirul de lungime maxima care apare atat in A cat si in B.
int a[100], b[100], c[200], n1, n2, dm, elem;
//cout<<"Introduceti nr de elem din primul sir: ";
//cin>>n1;
//cout<<"Introduceti nr de elem din cel de-al doilea sir: ";
//cin>>n2;
ifstream.cmlsc_in;
cmlsc_in.open ("cmlsc_in.txt");
ofstream.cmlsc_out;
cmlsc_out.open ("cmlsc_out.txt");
for (int i=0; i<n1; i++)
{
cmlsc_in>>a[i];
}
for (int i=0; i<n2; i++)
{
cmlsc_in>>b[i];
}
if (n1<n2)
{
dm=n1;
}
else
{
dm=n2;
}
for (int i=0; i<n1; i++)
{
for(int j=0; j<n2; j++)
{
if (a[i]=b[i])
{
elem=a[i];
c[i]=elem;
}
}
}
for (int i=0; i<dm; i++)
{
cmlsc_out<<c[i];
}
*/
/*
//Sa se determine un subsir al lui a care este ordonat strict crescator si care are lungimea maxima.
int a[100], b[100], n, k=0;
int temp = 0;
//cout<<"Introduceti nr de elem din primul sir: ";
ifstream scmax_in;
scmax_in.open ("scmax_in.txt");
ofstream scmax_out;
scmax_out.open ("scmax_out.txt");
scmax_in>>n;
for (int i=0; i<n; i++)
{
scmax_in>>a[i];
}
b[0] = 0;
for (int i=0; i<n; i++)
{
if (a[i] > temp)
{
b[k]=a[i];
temp = b[k];
k++;
}
}
for (int i=0; i<k; i++)
{
scmax_out<<b[i]<<" ";
}
*/
/*
//Sa se genereze toate permutarile multimii {1, 2, ...N}, in ordine lexicografica.
int a[100], b[100], i, n;
cout<<"Introduceti nr de elemenete din sir: ";
cin>>n;
for (i=0; i<n; i++)
{
cout<<"a["<<i<<"]="<<a[i];
cin>a[i];
}
for (i=0; i<n; i++)
{
cout<<a[i];
}
for ()
*/
/*
//A+B --> Adunare simplă.
int a, b;
ifstream fin;
fin.open ("fin.txt")
ofstream fout;
fout.open ("fout.txt")
fin>>a>>b;
fout<<a+b;
*/
/*
int n, p=1;
ifstream fin;
fin.open ("fin.txt")
ofstream fout;
fout.open ("fout.txt")
fin>>n;
for (int i=1; i<=n; i++)
{
p*=i;
}
fout<<p;
*/
return 0;
}