Cod sursa(job #153036)

Utilizator MariusMarius Stroe Marius Data 10 martie 2008 01:41:14
Problema Pedefe Scor 90
Compilator cpp Status done
Runda Arhiva de probleme Marime 2.22 kb
#include <fstream>
#include <algorithm>

using namespace std;

const char iname[] = "pedefe.in";
const char oname[] = "pedefe.out";

#define FOR(i, a, b)  for (int i = (a); i <= (b); ++ i)
#define FORR(i, b, a) for (int i = (b); i >= (a); -- i)
#define lastbit(x) ((x) ^ ((x) & ((x) - 1)))

#define MAXN	  505
#define MAXVALUE  505

#define modulo 666013

int A[MAXN], B[MAXN], C[MAXN];

int Cnt[2][MAXN][MAXN], Sum[2][MAXN][MAXN], SumV[2][MAXVALUE][MAXN];


inline void update(int &var, int val) {
	if (val < 0)
		val += modulo;
	if ((var += val) >= modulo)
		var -= modulo;
}

int query(int s, int i, int j) 
{
	int ret = 0;
	for (; i > 0; i -= lastbit(i))
		if ((ret += SumV[s][i][j]) >= modulo)
			ret -= modulo;
	return ret;
}

void update(int s, int i, int j, int val) 
{
	for (; i < MAXVALUE; i += lastbit(i))
		if ((SumV[s][i][j] += val) >= modulo)
			SumV[s][i][j] -= modulo;
}

int main(void)
{
	int n, m, p;

	ifstream fin(iname);

	fin >> n >> m >> p;
	FOR (i, 1, n) 
		fin >> A[i];
	FOR (i, 1, m) 
		fin >> B[i];
	FOR (i, 1, p) 
		fin >> C[i];

	fin.close();

	int s = 0;
	
	FOR (i, 1, n)
	{
		FOR (j, 1, m)
			Sum[s][i][j] = query(s, A[i], j);

		FOR (j, 1, m) if (A[i] == B[j])
		{
			Cnt[s][i][j] = 1;
			update(Cnt[s][i][j], Sum[s][i][1] - Sum[s][i][j]);
		}
		
		int tsum = 0;
		FORR (j, m, 1) {
			if ((tsum += Cnt[s][i][j]) >= modulo)
				tsum -= modulo;
			update(s, A[i], j, tsum);
		}
	}

	FOR (k, 1, p) 
	{
		s = k & 1;
		memset(SumV[s], 0, sizeof(SumV[s]));
		
		FOR (i, 1, n)
		{
			FOR (j, 1, m)
				Sum[s][i][j] = query(s, A[i], j);

			FOR (j, 1, m) if (A[i] == B[j]) 
			{
				Cnt[s][i][j] = 0;

				if (A[i] == C[k])
				{
					if (k == 1)
						Cnt[s][i][j] = 1;
					update(Cnt[s][i][j], Sum[s ^ 1][i][1] - Sum[s ^ 1][i][j]);
				} 
				else
					update(Cnt[s][i][j], Sum[s][i][1] - Sum[s][i][j]);
			}

			int tsum = 0;
			FORR (j, m, 1) {
				if ((tsum += Cnt[s][i][j]) >= modulo)
					tsum -= modulo;
				update(s, A[i], j, tsum);
			}
		}
	}

	int ret = 0;

	FOR (i, 1, n) FOR (j, 1, m) if (A[i] == B[j]) 
		update(ret, Cnt[p & 1][i][j]);

	ofstream fout(oname);	fout << ret <<'\n';  fout.close();

	return 0;
}