Cod sursa(job #1501018)

Utilizator cosmin.pascaruPascaru Cosmin cosmin.pascaru Data 12 octombrie 2015 22:42:25
Problema Cuplaj maxim in graf bipartit Scor 90
Compilator cpp Status done
Runda Arhiva educationala Marime 1.34 kb
#include <iostream>
#include <cstdio>
#include <vector>
#include <bitset>
#include <utility>
#include <algorithm>

#define NMAX 10005
#define pb push_back

using namespace std;

vector<int> G[NMAX];
int L[NMAX], R[NMAX];
bitset<NMAX> U;
int n, m, e;

bool pairup(int nod)
{
    if (U[nod]) return 0;
    U[nod] = 1;
    
    for (vector<int> :: iterator it = G[nod].begin(); it != G[nod].end(); ++it)
        if (!R[*it])
        {
            L[nod] = *it;
            R[*it] = nod;
            return 1;
        }
    for (vector<int> :: iterator it = G[nod].begin(); it != G[nod].end(); ++it)
        if (pairup(R[*it]))
        {
            L[nod] = *it;
            R[*it] = nod;
            return 1;
        }
    return 0;
}
int main()
{
    freopen("cuplaj.in", "rt", stdin);
    freopen("cuplaj.out", "w", stdout);
    
    int x, y;
    
    cin >> n >> m >> e;
    for (int i = 0; i < e; ++i)
    {
        cin >> x >> y;
        G[x].push_back(y);
    }
    
    for (bool change = 1; change;)
    {
        change = 0;
        U.reset();
        for (int i = 1; i <= n; ++i)
            if (!L[i]) change |= pairup(i);
    }
    
    int dimCuplaj = 0;
    for (int i = 1; i <= n; ++i)
        if (L[i]) ++dimCuplaj;
    cout << dimCuplaj << '\n';
    
    for (int i = 1; i <= n; ++i)
        if (L[i]) cout << i << ' ' << L[i] << '\n';
    return 0;
}