///Solutie explicata de marele matematician Tudor Bonifate

#include <bits/stdc++.h>

using namespace std;

int T , a , b , c , cmmdc;
int x , y;

int Euclid(int a , int b , int &x , int &y)
{
    if (!b)
    {
        x = 1; y = 0;
        return a;
    }

    int x0 , y0 , d = Euclid(b , a % b , x0 , y0);

    x = y0;
    y = x0 - (a / b) * y0;

    return d;
}

int main()
{
    freopen("euclid3.in","r",stdin);
    freopen("euclid3.out","w",stdout);

    for (scanf("%d", &T); T; --T)
    {
        scanf("%d %d %d", &a, &b, &c);

        cmmdc = Euclid(a , b , x , y);

        if (c % cmmdc != 0)
        {
            printf("0 0\n");
            continue;
        }

        printf("%d %d\n", x * c / cmmdc , y * c / cmmdc);
    }

    return 0;
}