Borderou de evaluare (job #1491499)

Utilizator armandpredaPreda Armand armandpreda Data 25 septembrie 2015 16:30:13
Problema Hercule Status done
Runda Arhiva de probleme Compilator cpp | Vezi sursa
Scor 0

Raport evaluator

Eroare de compilare: user.cpp:10:6: error: ‘bool exit’ redeclared as different kind of symbol bool exit, viz[LIM+1]; ^ In file included from /usr/include/c++/4.8/cstdlib:72:0, from /usr/include/c++/4.8/ext/string_conversions.h:41, from /usr/include/c++/4.8/bits/basic_string.h:2815, from /usr/include/c++/4.8/string:52, from /usr/include/c++/4.8/bits/locale_classes.h:40, from /usr/include/c++/4.8/bits/ios_base.h:41, from /usr/include/c++/4.8/ios:42, from /usr/include/c++/4.8/istream:38, from /usr/include/c++/4.8/fstream:38, from user.cpp:1: /usr/include/stdlib.h:544:13: error: previous declaration of ‘void exit(int)’ extern void exit (int __status) __THROW __attribute__ ((__noreturn__)); ^ user.cpp: In function ‘void back(int, int)’: user.cpp:24:13: error: assignment of function ‘void exit(int)’ exit=1; ^ user.cpp:24:13: error: cannot convert ‘int’ to ‘void(int)throw ()’ in assignment user.cpp:26:17: warning: the address of ‘void exit(int)’ will always evaluate as ‘true’ [-Waddress] if(tot>n or exit) return; ^ user.cpp:33:20: warning: the address of ‘void exit(int)’ will always evaluate as ‘true’ [-Waddress] if(exit) return; ^ user.cpp: In function ‘int main()’: user.cpp:43:13: warning: the address of ‘void exit(int)’ will always evaluate as ‘true’ [-Waddress] if(!exit) ^ user.cpp:45:13: error: assignment of function ‘void exit(int)’ exit=0; ^ user.cpp:45:13: error: cannot convert ‘int’ to ‘void(int)throw ()’ in assignment

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