Borderou de evaluare (job #1486585)
Utilizator | Data | 15 septembrie 2015 09:49:16 | |
---|---|---|---|
Problema | Trans | Status | done |
Runda | Arhiva de probleme | Compilator | c | Vezi sursa |
Scor | 0 |
Raport evaluator
Eroare de compilare:
user.c:4:8: error: unknown type name ‘P’
void I(P d[],P &a,P e) {
^
user.c:4:14: error: unknown type name ‘P’
void I(P d[],P &a,P e) {
^
user.c:4:19: error: unknown type name ‘P’
void I(P d[],P &a,P e) {
^
user.c:8:7: error: unknown type name ‘P’
int Q(P d[],P &a,int j) {
^
user.c:8:13: error: unknown type name ‘P’
int Q(P d[],P &a,int j) {
^
user.c: In function ‘W’:
user.c:13:2: error: unknown type name ‘P’
P d[2][16001],e,r,a[2];
^
user.c:14:3: error: request for member ‘x’ in something not a structure or union
e.x=e.y=0,a[0].x=a[0].y=a[1].x=a[1].y=1,d[0][1]=d[1][1]=e;
^
user.c:14:7: error: request for member ‘y’ in something not a structure or union
e.x=e.y=0,a[0].x=a[0].y=a[1].x=a[1].y=1,d[0][1]=d[1][1]=e;
^
user.c:14:16: error: request for member ‘x’ in something not a structure or union
e.x=e.y=0,a[0].x=a[0].y=a[1].x=a[1].y=1,d[0][1]=d[1][1]=e;
^
user.c:14:23: error: request for member ‘y’ in something not a structure or union
e.x=e.y=0,a[0].x=a[0].y=a[1].x=a[1].y=1,d[0][1]=d[1][1]=e;
^
user.c:14:30: error: request for member ‘x’ in something not a structure or union
e.x=e.y=0,a[0].x=a[0].y=a[1].x=a[1].y=1,d[0][1]=d[1][1]=e;
^
user.c:14:37: error: request for member ‘y’ in something not a structure or union
e.x=e.y=0,a[0].x=a[0].y=a[1].x=a[1].y=1,d[0][1]=d[1][1]=e;
^
user.c:14:11: warning: left-hand operand of comma expression has no effect [-Wunused-value]
e.x=e.y=0,a[0].x=a[0].y=a[1].x=a[1].y=1,d[0][1]=d[1][1]=e;
^
user.c:14:41: warning: left-hand operand of comma expression has no effect [-Wunused-value]
e.x=e.y=0,a[0].x=a[0].y=a[1].x=a[1].y=1,d[0][1]=d[1][1]=e;
^
user.c:17:13: warning: implicit declaration of function ‘Q’ [-Wimplicit-function-declaration]
b[i][c]=Q(d[c],a[c],i-K)+s[i][c]+T;
^
user.c:19:14: error: request for member ‘x’ in something not a structure or union
r.x=i,r.y=(b[i][0]<b[i][1]?b[i][0]:b[i][1])-s[i][c],I(d[c],a[c],r);
^
user.c:19:20: error: request for member ‘y’ in something not a structure or union
Ceva nu functioneaza?
- Citeste despre borderoul de evaluare.
- Daca tot nu e bine, contacteaza-ne pe forum !