#define REP(a,b) for(int a=0; a<(b); ++a)
#define REP2(a,b) for(int a=1; a<=(b); ++a)
#define FWD(a,b,c) for(int a=(b); a<(c); ++a)
#define BCK(a,b,c) for(int a=(b)-1; a>=(c); --a)
#define BCK2(a,b,c) for(int a=(b); a>(c); --a)
#define FWDS(a,b,c,d) for(int a=(b); a<(c); a+=d)
#define ALL(a) (a).begin(), (a).end()
#define SIZE(a) ((int)(a).size())
#define VAR(x) #x ": " << x << " "
#define FILL(x,y) memset(x,y,sizeof(x))
#define MIN(a,b) (((a)<(b))?(a):(b))
#define MAX(a,b) (((a)>(b))?(a):(b))
#define FAST ios_base::sync_with_stdio(0);cin.tie(0);
#define x first
#define y second
#define st first
#define nd second
#define mp make_pair
#define pb push_back
#define l(n) (n<<1)
#define r(n) ((n<<1)+1)
#define f(n) (n>>1)
#define lsb(a) (a&-a)
#include<vector>
#include<stack>
#include<queue>
#include<algorithm>
using namespace std;
#ifndef ONLINE_JUDGE
#include<fstream>
ifstream cin("lca.in");
ofstream cout("lca.out");
#else
#include<iostream>
#endif
const int NMAX = 100069;
const int PMAX = 1015;
const int INF = 1 << 31;
const int dx[] = {0, 0, -1, 1}; //1,1,-1,1};
const int dy[] = {-1, 1, 0, 0}; //1,-1,1,-1};
typedef long long LL;
typedef pair<int, int> PII;
typedef long double K;
typedef pair<K, K> PKK;
typedef vector<int> VI;
int x,y;
int a,b,sol,p;
int n,m;
int s[NMAX], v;
int h[NMAX<<1], k;
int d[NMAX<<1];
int pos[NMAX];
int Log[NMAX], rmq[21][NMAX];
VI G[NMAX];
void dfs(int i, int lvl)
{
// log in
h[++k]=i;
d[k]=lvl;
pos[i]=k;
REP(j,G[i].size())
{
dfs(G[i][j], lvl+1);
// log in
h[++k]=i;
d[k]=lvl;
}
}
int main(){
FAST;
cin>>n>>m;
for(int i=2; i<=n; ++i)
cin>>x,
G[x].push_back(i);
// DFS to construct the Euler traversal in h[k].
dfs(1,0);
// RMQ preprocessing
for(int i=2; i<=k; ++i)
Log[i]=Log[i>>1] + 1;
for(int i=1; i<=k; ++i)
rmq[0][i]=i;
for(int i=1; (1<<i) < k; ++i)
for(int j=1; j + (1<<i) <= k; ++j){
rmq[i][j]=rmq[i-1][j];
if(d[rmq[i-1][j+(1<<(i-1))]]< d[rmq[i][j]])
rmq[i][j]=rmq[i-1][j+(1<<(i-1))];
}
//Respond to queries:
REP(i,m)
{
cin>>x>>y;
a=pos[x], b=pos[y]; // increment so it will be inclusive: [a,b]
if(a>b)
swap(a,b);
p=Log[b-a];
sol=rmq[p][a];
if(d[sol] > d[rmq[p][b-(1<<p)]])
sol=rmq[p][b-(1<<p)];
cout<<h[sol]<<"\n";
}
return 0;
}