#include <cstdio>
#include <algorithm>
#include <cstring>
#include <vector>
#define maxN 200002
#define inf 2000000000
using namespace std;
int n, N, i, j, m, sol, cost[maxN], nre, t[maxN], r, minv, poz[maxN];
bool used[maxN];
int H[maxN * 2];
inline int father(int nod) {
return nod / 2;
}
inline int left_son(int nod) {
return nod * 2;
}
inline int right_son(int nod) {
return nod * 2 + 1;
}
struct edge
{
int x;
int y;
}e[maxN];
void sift(int N, int K) {
int son;
do {
son = 0;
if (left_son(K) <= N) {
son = left_son(K);
if (right_son(K) <= N && cost[H[right_son(K)]] < cost[H[left_son(K)]]) {
son = right_son(K);
}
if (cost[H[son]] >= cost[H[K]]) {
son = 0;
}
}
if (son) {
swap(poz[H[K]], poz[H[son]]);
swap(H[K], H[son]);
K = son;
}
} while (son);
}
void percolate(int N, int K) {
int key = H[K];
while ((K > 1) && (cost[key] < cost[H[father(K)]])) {
H[K] = H[father(K)];
poz[H[father(K)]] = K;
K = father(K);
}
H[K] = key;
poz[key] = K;
}
void cut(int& N, int K) {
if (N == K)
{
poz[H[K]] = 0;
-- N;
return ;
}
H[K] = H[N];
poz[H[N]] = K;
--N;
if ((K > 1) && (cost[H[K]] < cost[H[father(K)]])) {
percolate(N, K);
} else {
sift(N, K);
}
}
void insert(int& N, int key) {
H[++N] = key;
poz[key] = N;
percolate(N, N);
}
vector < pair < int, int > > V[maxN];
void read()
{
int x, y, z;
freopen("apm.in", "r", stdin);
freopen("apm.out", "w", stdout);
scanf("%d %d", &n, &m);
minv = inf;
for (i = 1; i <= m; ++ i)
{
scanf("%d %d %d", &x, &y, &z);
if (z < minv)
minv = z,
r = x;
V[x].push_back(make_pair(y, z));
V[y].push_back(make_pair(x, z));
}
}
void solve()
{
int x, node;
r = 1; N = 0;
for (i = 1; i <= n; ++ i)
{
if (i != r)
cost[i] = inf;
}
insert(N, 1);
while (N)
{
x = H[1];
cut(N, 1);
poz[x] = 0;
if (nre == n)
break;
used[x] = 1;
sol += cost[x];
e[++ nre].x = t[x];
e[nre].y = x;
for (i = 0; i < V[x].size(); ++ i)
{
node = V[x][i].first;
if (!used[node] && V[x][i].second < cost[node])
{
t[node] = x;
cost[node] = V[x][i].second;
if (poz[node])
cut(N, poz[node]);
insert(N, node);
}
}
}
}
void write()
{
freopen("apm.out", "w", stdout);
printf("%d\n%d\n", sol, nre - 1);
for (i = 2; i <= nre; ++ i)
printf("%d %d\n", e[i].x, e[i].y);
}
int main()
{
read();
solve();
write();
}