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#ifdef ONLINE_JUDGE
#include <bits/stdc++.h>
#else
#include <algorithm>
#include <bitset>
#include <cassert>
#include <cmath>
#include <cstdio>
#include <cstdlib>
#include <cstring>
#include <iostream>
#include <map>
#include <set>
#include <stack>
#include <string>
#include <utility>
#include <vector>
#include <queue>
#include <climits>
#endif
using namespace std;
// lambda : [] (int a, int b) -> bool { body return }
// string r_str = R"(raw string)"
#define mp make_pair
#define mt make_tuple
#define eb emplace_back
#define pb push_back
#define LL long long
#define ULL unsigned long long
#define BASE 73
#define NMAX 10000
#define NMAX2 20001
#define MOD1 1000000007
#define ALL(V) (V).begin(), (V).end()
#define ALLR(V) (V).rbegin(), (V).rend()
#define CRLINE Duxar(__LINE__);
#define SHOWME(x) cerr << __LINE__ << ": " << #x << " = " << (x) << endl;
#define ENTER putchar('\n');
int dx4[] = {-1, 0, 1, 0};
int dy4[] = {0, 1, 0, -1};
int dx8[] = {-1, -1, 0, 1, 1, 1, 0, -1};
int dy8[] = {0, 1, 1, 1, 0, -1, -1, -1};
void Duxar(int _this_line) {
#ifndef ONLINE_JUDGE
printf("\n . . . . . . . . . . . . . Passed line - %d\n", _this_line);
#endif
}
template <class T>
void ReadNo(T &_value) {
T _sign = 1;
char ch;
_value = 0;
while(!isdigit(ch = getchar())) {
(ch == '-') && (_sign = -1);
}
do {
_value = _value * 10 + (ch - '0');
} while(isdigit(ch = getchar()));
_value *= _sign;
}
int N, M;
vector <vector <int> > rmq;
vector <int> log_of;
int main(){
string file_input = "rmq";
#ifdef INFOARENA
freopen((file_input + ".in").c_str(), "r", stdin);
freopen((file_input + ".out").c_str(), "w", stdout);
#else
#ifndef ONLINE_JUDGE
freopen("input.cpp", "r", stdin);
#endif
#endif
int i, x, y, lg, k;
ReadNo(N); ReadNo(M);
log_of.resize(N + 1);
for (i = 2; i <= N; ++i) {
log_of[i] = log_of[i >> 1] + 1;
}
rmq.resize(log_of[N] + 1);
rmq[0].resize(N + 1);
for (i = 1; i <= N; ++i) {
ReadNo(rmq[0][i]);
}
for (k = 1; k <= log_of[N]; ++k) {
rmq[k].resize(N - (1 << k) + 2);
for (i = 1; i + (1 << k) - 1 <= N; ++i) {
rmq[k][i] = min(rmq[k - 1][i], rmq[k - 1][i + (1 << (k - 1))]);
}
}
for (i = 1; i <= M; ++i) {
ReadNo(x); ReadNo(y);
lg = y - x + 1;
k = log_of[lg];
printf("%d\n", min(rmq[k][x], rmq[k][y - (1 << k) + 1]));
}
return 0;
}