Cod sursa(job #145968)

Utilizator savimSerban Andrei Stan savim Data 29 februarie 2008 19:53:53
Problema Lupul Urias si Rau Scor 20
Compilator cpp Status done
Runda Arhiva de probleme Marime 2.05 kb
#include <stdio.h>
#define maxl 100010
int o,t,i,j,k,n,x,l;
int d[maxl],a[maxl],b[maxl][2];
int h[maxl];
long long sum=0;
void inter(int p, int q)
{
	 int r=(p+q)/2,i,x=p,y=r+1;
	 k=0;
	 while (x<=r && y<=q)
	 {
		k++;
		if (d[x]<d[y]) {b[k][0]=d[x];b[k][1]=a[x];x++;}
		else {b[k][0]=d[y];b[k][1]=a[y];y++;}
	 }
	 while (x<=r) {k++;b[k][0]=d[x];b[k][1]=a[x];x++;}
	 while (y<=q) {k++;b[k][0]=d[y];b[k][1]=a[y];y++;}
	 k=0;
	 for (i=p; i<=q; i++) {k++;d[i]=b[k][0];a[i]=b[k][1];}
}
void inter2(int p, int q)
{
	 int r=(p+q)/2,i,x=p,y=r+1;
	 k=0;
	 while (x<=r && y<=q)
	 {
		k++;
		if (a[x]<a[y]) {b[k][0]=d[x];b[k][1]=a[x];x++;}
		else {b[k][0]=d[y];b[k][1]=a[y];y++;}
	 }
	 while (x<=r) {k++;b[k][0]=d[x];b[k][1]=a[x];x++;}
	 while (y<=q) {k++;b[k][0]=d[y];b[k][1]=a[y];y++;}
	 k=0;
	 for (i=p; i<=q; i++) {k++;d[i]=b[k][0];a[i]=b[k][1];}
}
void merge(int p, int q)
{
	int r=(p+q)/2;
	if (p==q) return;
	merge(p,r);
	merge(r+1,q);
	inter(p,q);
	if (p>=q) return;
}
int main()
{
	freopen("lupu.in","r",stdin);
    freopen("lupu.out","w",stdout);
    
    scanf("%d %d %d",&n,&x,&l);    
    for (i=1; i<=n; i++)
        scanf("%d %d",&d[i],&a[i]);
    
	for (i=1; i<=n; i++) 
     if (d[i]>x) d[i]=-1;     
     else d[i]=(x-d[i])/l;

	merge(1,n);

	k=0;
	int timp=-1;d[0]=d[1]-1;
	for (i=n; i>=1; i--)
	if (d[i]!=timp && d[i]>=0)
	{
		 for (j=i; j>=1; j--)
		 if (d[j]==d[i])
		 {
			k++;
			h[k]=a[j];
			x=k;
			while (x/2>0)
			{
				if (h[x/2]<h[x]) {t=h[x/2];h[x/2]=h[x];h[x]=t;}
				x/=2;
			}
		}
		else {o=d[j];break;}

		l=0;

		if (o==-1) {l=1; o=d[i]-1;}
		if (o==d[i]) o=d[i]-1;

		for (j=o+1; j<=d[i]; j++)
		{
			sum+=h[1];
			// eliminare pozitia 1 din heap

			t=h[1];h[1]=h[k];h[k]=t;k--;

			if (k==0) break;
			x=1;
			while (x<=k)
			{
				if (h[x]<h[2*x]) {t=h[2*x];h[2*x]=h[x];h[x]=t;k=2*x;}
				else if (2*x+1<=k && h[x]<h[2*x+1]) {t=h[2*x+1];h[2*x+1]=h[x];h[x]=t;x=2*x+1;}
					 else break;
			}
		}
		timp=d[i];
		if (l) break;
	}
	printf("%lld\n",sum);
	return 0;
}