#include <iostream>
#include <fstream>
#include <cmath>
using namespace std;
ifstream f("cifra.in");
ofstream g("cifra.out");
int i,s=0,n,v[1000],j,t;
string c[10000];
int main()
{
    f>>t;
    for (i=1;i<=t;i++)
        f>>c[i];
    return 0;
}
void sum()
{
    for (i=1;i<=t;i++)
    {
        s=s+pow(c[i][0]-'0',c[i][0]-'0');
        g<<s%10<<"\n";
    }
}