Cod sursa(job #1415473)
Utilizator | Data | 4 aprilie 2015 18:33:16 | |
---|---|---|---|
Problema | Ridicare la putere in timp logaritmic | Scor | 100 |
Compilator | cpp | Status | done |
Runda | Arhiva educationala | Marime | 0.45 kb |
#include <iostream>
#include <cstdio>
#define MOD 1999999973
using namespace std;
long long pow,k;
int main()
{
freopen("lgput.in", "r", stdin);
freopen("lgput.out", "w", stdout);
long long answer=1;
scanf("%lld %lld",&pow,&k);
while(k)
{
if(k&1) // k%2==1
answer=(answer*pow)%MOD;
pow=pow*pow%MOD;
k >>= 1; // k=k/2
}
printf("%lld",answer);
return 0;
}