Pagini recente » Cod sursa (job #3272065) | Cod sursa (job #980951) | Cod sursa (job #317777) | Cod sursa (job #2725059) | Cod sursa (job #1387734)
#include <iostream>
#include <climits>
#include <cmath>
#include <fstream>
#define MAX 1000004
using namespace std;
int auxiliary[MAX];
int prime[MAX];
void init(long long n){
for (long long i = 2; i <= n; i++){
auxiliary[i] = 1;
prime[i] = i;
}
}
void prime_numbers(long long n){
for (long long i = 2; i <= n; i++){
if (auxiliary[i] == 1){
prime[i] = i-1;
for (long long j = i*2; j <= n; j = j + i){
auxiliary[j] = 0;
prime[j] = prime[j] * (i-1)/i;
}
}
}
return ;
}
long long number_of_fractions(long long n){
long long contor = 0;
for (long long i = 2; i <= n; i++){
contor += prime[i];
}
return (contor * 2 + 1);
}
int main(void){
long long result = 0;
long long n;
ifstream in;
ofstream out;
in.open("fractii.in");
out.open("fractii.out");
in >> n;
init(n);
prime_numbers(n);
result = number_of_fractions(n);
out << result;
in.close();
out.close();
return 0;
}