Borderou de evaluare (job #1375492)

Utilizator FlorinHajaFlorin Gabriel Haja FlorinHaja Data 5 martie 2015 13:23:26
Problema Suma si numarul divizorilor Status done
Runda Arhiva educationala Compilator cpp | Vezi sursa
Scor 0

Raport evaluator

Eroare de compilare: user.cpp:9:16: error: ‘int div [1000001]’ redeclared as different kind of symbol int div[1000001], m, n, i, j; ^ In file included from /usr/include/c++/4.8/cstdlib:72:0, from /usr/include/c++/4.8/ext/string_conversions.h:41, from /usr/include/c++/4.8/bits/basic_string.h:2815, from /usr/include/c++/4.8/string:52, from /usr/include/c++/4.8/bits/locale_classes.h:40, from /usr/include/c++/4.8/bits/ios_base.h:41, from /usr/include/c++/4.8/ios:42, from /usr/include/c++/4.8/istream:38, from /usr/include/c++/4.8/fstream:38, from user.cpp:1: /usr/include/stdlib.h:785:14: error: previous declaration of ‘div_t div(int, int)’ extern div_t div (int __numer, int __denom) ^ user.cpp: In function ‘void ciur()’: user.cpp:19:23: error: invalid types ‘<unresolved overloaded function type>[int]’ for array subscript m++, div[m] = i; ^ user.cpp: In function ‘int main()’: user.cpp:34:26: error: invalid types ‘<unresolved overloaded function type>[int]’ for array subscript for (j = 1; div[j]*div[j] <= y; j++) ^ user.cpp:34:33: error: invalid types ‘<unresolved overloaded function type>[int]’ for array subscript for (j = 1; div[j]*div[j] <= y; j++) ^ user.cpp:36:22: error: invalid types ‘<unresolved overloaded function type>[int]’ for array subscript q = div[j], nr = 0; ^ user.cpp:38:29: error: invalid types ‘<unresolved overloaded function type>[int]’ for array subscript while (x % div[j] == 0) ^ user.cpp:39:27: error: invalid types ‘<unresolved overloaded function type>[int]’ for array subscript x /= div[j], nr++, q *= div[j]; ^ user.cpp:39:46: error: invalid types ‘<unresolved overloaded function type>[int]’ for array subscript x /= div[j], nr++, q *= div[j]; ^ user.cpp:41:49: error: invalid types ‘<unresolved overloaded function type>[int]’ for array subscript nrd *= (nr+1)%MOD, s *= (q-1)/(div[j]-1)%MOD; ^

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