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Cod sursa(job #122602)
#include <fstream.h>
int n,a[5500],b[5500],c[5500],nr;
void citire()
{
ifstream fin("nunta.in");
fin>>n;
fin.close();
}
void suma()
{
a[5000]=1;
b[5000]=1;
nr=1;
int t=0;
for (int i=0;i<n;i++)
{
t=0;
for (int l=0;l<=5000;l++)
{
int aux=a[l];
a[l]=b[l];
b[l]=aux;
}
for (int j=5000;j>5000-nr;j--)
{
a[j]+=b[j]+t;
t=a[j]/10;
a[j]=a[j]%10;
}
if (t==1)
a[5000-(nr++)]=1;
}
}
void afisare()
{
ofstream fout("nunta.out");
if (n==1)
fout<<"1";
else
if (n==2)
fout<<"2";
else
{
for (int i=5000-nr+1;i<=5000;i++)
fout<<b[i]; }
fout<<"\n";
fout.close();
}
int main()
{
citire();
suma();
afisare();
return 0;
}