Borderou de evaluare (job #1213523)

Utilizator mihail.jianuJianu Mihail mihail.jianu Data 28 iulie 2014 13:18:18
Problema Farfurii Status done
Runda Arhiva de probleme Compilator cpp | Vezi sursa
Scor 0

Raport evaluator

Eroare de compilare: user.cpp:2:12: error: expected unqualified-id before ‘,’ token const long ,ong N=100000; ^ user.cpp:2:17: error: expected initializer before ‘N’ const long ,ong N=100000; ^ user.cpp:3:10: error: ‘N’ was not declared in this scope bool vis[N+1]; ^ user.cpp: In function ‘void scan()’: user.cpp:7:33: warning: format ‘%d’ expects argument of type ‘int*’, but argument 3 has type ‘long long int*’ [-Wformat=] fscanf(in,"%I64d%I64d",&n,&k); ^ user.cpp:7:33: warning: format ‘%d’ expects argument of type ‘int*’, but argument 4 has type ‘long long int*’ [-Wformat=] user.cpp: In function ‘void solve()’: user.cpp:21:9: error: ‘vis’ was not declared in this scope vis[i]=true; ^ user.cpp:22:31: warning: format ‘%d’ expects argument of type ‘int’, but argument 3 has type ‘long long int’ [-Wformat=] fprintf(out,"%I64d ",i); ^ user.cpp:25:36: warning: format ‘%d’ expects argument of type ‘int’, but argument 3 has type ‘long long int’ [-Wformat=] fprintf(out,"%I64d ",k-nr+i); ^ user.cpp:26:9: error: ‘vis’ was not declared in this scope vis[k-nr+i]=true; ^ user.cpp:29:13: error: ‘vis’ was not declared in this scope if(!vis[i]) ^ user.cpp:30:35: warning: format ‘%d’ expects argument of type ‘int’, but argument 3 has type ‘long long int’ [-Wformat=] fprintf(out,"%I64d ",i); ^ user.cpp: In function ‘void scan()’: user.cpp:7:34: warning: ignoring return value of ‘int fscanf(FILE*, const char*, ...)’, declared with attribute warn_unused_result [-Wunused-result] fscanf(in,"%I64d%I64d",&n,&k); ^

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