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Cod sursa(job #119759)
#include <cstdio>
#include <vector>
using namespace std;
#define DxBG
#define FL
#define fin "pairs.in"
#define fout "pairs.out"
const int Vmax = 1001100;
const int Nmax = 100100;
int N,MAX;
int nr[Nmax];
int divnr[10];
vector <int> v;
long long cnt1; //cate is bune
long long cnt2; //cate au cmmdc>1
//v[i] - cate numere se divid cu i
//nr - numerele date
//div[i] - divizorii numarului nr[i]
void readdata()
{
int i;
freopen(fin,"r",stdin);
scanf("%d",&N);
for (i=1;i<=N;++i)
{
scanf("%d",&nr[i]);
if ( nr[i] > MAX )
MAX = nr[i];
}
++MAX;
v.resize(MAX);
for (i=1;i<=N;++i)
v[ nr[i] ] = 1;
}
inline void afla(int a)
{
int j,bun;
divnr[0]=0;
for (j=2;j*j<=a;++j)
{
bun=0;
while (a%j==0)
{
bun=1;
a/=j;
}
if (bun)
divnr[++divnr[0]]=j;
}
if (a>1)
divnr[++divnr[0]]=a;
}
void solve()
{
int i,j,k,nrb,tmp;
int cnt;
//aflu fiecare numar "i" cu cate numere din "nr" se divide
for (i=2;i<MAX;++i)
for (j=i+i;j<MAX;j+=i)
if (v[j]) ++v[i];
//gata
#ifdef DBG
for (i=1;i<=MAX;++i)
printf("%d ",v[i]);
printf("\n");
#endif
cnt1 = N-1;
cnt1 = cnt1 * N;
cnt1 = cnt1 / 2;
cnt2 = 0;
//incep rezolvarea propriu-zisa
for (i=1;i<=N;++i)
{
cnt = 0; //numar perechi care au cmmdc( nr[i] , a ) > 1
afla(nr[i]);
//excludere si includere
for (j=1;j<(1<<divnr[0]);++j)
{
nrb = 0;
tmp = 1;
for (k=0;(1<<k)<=j;++k)
if (j&(1<<k))
{
++nrb;
tmp*=divnr[k+1];
}
if (nrb&1)
cnt+=(v[tmp]-1);
else
cnt-=(v[tmp]-1);
}
//gata
cnt2+=cnt;
#ifdef DBG
printf("%d %d\n",i,cnt);
#endif
}
cnt2/=2;
cnt1-=cnt2;
#ifdef FL
freopen(fout,"w",stdout);
#endif
printf("%lld\n",cnt1);
}
int main()
{
readdata();
solve();
return 0;
}