Cod sursa(job #1165454)

Utilizator gabrielinelusGabriel-Robert Inelus gabrielinelus Data 2 aprilie 2014 18:20:53
Problema Suma si numarul divizorilor Scor 100
Compilator cpp Status done
Runda Arhiva educationala Marime 1.57 kb
#include <cstdio>
#include <bitset>

using namespace std;

#define Nmax  1000005
#define MOD 9973
bitset<Nmax> used;

int N,nrp;
int is_prime[80000];

void precalc()
{
    is_prime[nrp++] = 2;
    for(int i = 1; ((i<<1)|1) <= Nmax; ++i)
        if(!used[((i<<1)|1)])
        {
            is_prime[ nrp++ ]= ((i<<1)|1);
            for(int j = 1;((i<<1)|1)*((j<<1)|1) <= Nmax ; ++j)
                used[((i<<1)|1)*((j<<1)|1)] = 1;
        }
}

int lg_put(int x, int b)
{
    if (b == 0) return 1;
    if (b == 1) return x;
    int x1=x,x2=1;
    while(b != 1){
        if(b&1)
            x2 = (1LL*x2 * x1)%MOD,b^=1;
        x1 = (1LL*x1 * x1)%MOD,b>>=1;
    }
    return (x1*x2)%MOD;
}


void solve()
{
    long long a,b;
    int nrd = 1,times = 0,sd = 1,x,y;
    scanf("%lld",&a);b = a;
    for(int i = 0; is_prime[i] *is_prime[i] <= a; ++i)
    {
        times = 0;
        while(a % is_prime[i] == 0)
        {
            ++times;
            a/= is_prime[i];
        }
        if(times)
        {
            nrd = nrd * (times + 1);
            x = (lg_put(is_prime[i],times + 1) - 1) % MOD ;
            y = (lg_put(is_prime[i]-1, MOD-2)) % MOD ;
            sd = (1LL*(( 1LL * sd * x )% MOD) * y) % MOD;
        }
        if(a == 1) break;
    }
    if(a > 1){nrd *= 2;sd = (1LL*sd*(a + 1))%MOD;}
    printf("%d %d\n",nrd,sd);
}

void read()
{
    scanf("%d",&N);
    while(N--)solve();
}

int main()
{
    freopen("ssnd.in","r",stdin);
    freopen("ssnd.out","w",stdout);

    precalc();
    read();
    return 0;
}