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#include <fstream>
//#include <iostream>
//#include <cstring>
#include <cstdio>
using namespace std;
ifstream fin("trie.in");
ofstream fout("trie.out");
int n, m, qk, lg;
char x[21];
struct tree
{
int n, out;
tree* v[27];
tree()
{
n=0;
out=0;
for(int i=0; i<27; i++)
v[i]=0;
}
};
tree *ant2= new tree;
void update_1(tree *ant, char *a)
{
if(a[0]==0)
{
ant->n++;
return;
}
else if(ant->v[a[0]-'a']==0)
{
ant->v[a[0]-'a']= new tree;
ant->out++;
}
update_1(ant->v[a[0]-'a'], a+1);
}
int update_2(tree *ant,char *a)
{
if(a[0]==0)
ant->n--;
else
if( update_2(ant->v[a[0]-'a'], a+1))
{
ant->out--;
ant->v[a[0]-'a']=0;
}
if(ant->out==0 && ant->n==0 && ant!=ant2)
{
delete ant;
return 1;
}
return 0;
}
int querry_1(tree *ant,char *a)
{
if(a[0]==0)
return ant->n;
else if(ant->v[a[0]-'a']==0) return 0;
return querry_1(ant->v[a[0]-'a'], a+1);
}
int querry_2(tree *ant,char *a)
{
if(a[0]==0 || ant->v[a[0]-'a']==0)
return 0;
else return (querry_2(ant->v[a[0]-'a'],a+1)+1);
}
int main()
{
int k;
while(fin>>k>>x)
{
if(k==0)
update_1(ant2,x);
else if(k==1)
update_2(ant2, x);
else if(k==2)
fout<<querry_1(ant2,x)<<'\n';
else if(k==3)
fout<<querry_2(ant2,x)<<'\n';
}
fin.close();
fout.close();
return 0;
}