Pagini recente » Cod sursa (job #94652) | Cod sursa (job #389021) | Cod sursa (job #1266301) | Cod sursa (job #727069) | Cod sursa (job #1012095)
#include <iostream>
#include <fstream>
using namespace std;
long ridicaLaPutere(int n,int p){
if(n<0){
ridicaLaPutere(1/n,-p);
}else if(p==0){
return 1;
}else if(p==1){
return n;
}else if(n%2!=0){
return n*ridicaLaPutere(n*n,(p-1)/2);
}else if(n%2==0){
return ridicaLaPutere(n*n,p/2);
}
}
int main()
{
fstream f("lgput.in");
int n=0,p=0;
f>>n>>p;
ofstream o("lgput.out");
o<<(ridicaLaPutere(n,p)%1999999973)<<endl;
return 0;
}