Pagini recente » Monitorul de evaluare | bruh | Profil Alina_ | Profil Simon2712 | Diferente pentru competition/solutie intre reviziile 2 si 3
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This is $O(N^3)$ because we compute the total happiness of some array of winners $O(N)$ times. Each computation requires $O(N)$ days, and on each day we go through all members in the list, and the list may have up to $O(N)$ people.
Note there are easier solutions for $11$ points, we showed this one because it is easier to get to the next step with it.
Note there are easier $O(N^3^)$ solutions, we showed this one because it is easier to get to the next step with it.
h2. $O(N^2^)$
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