Mai intai trebuie sa te autentifici.
Diferente pentru competition/solutie intre reviziile #2 si #1
Nu exista diferente intre titluri.
Diferente intre continut:
We must still treat the happiness of $0$, but it can be computed efficiently in a similar manner, using its segments of coin receiving and some partial sums.
The final complexity is $O(N)$ because we can obtain in $O(N)$ all the precomputations about $I(0)$ and $I(N)$ and we can print each of the $N + 1$ numbers using $O(1)$ time. h3. Request Contacteaza-l pe autor daca te oferi sa traduci enuntul in limba romana.
The final complexity is $O(N)$ because we can obtain in $O(N)$ all the precomputations about $I(0)$ and $I(N)$ and we can print each of the $N + 1$ numbers using $O(1)$ time.
