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We must still treat the happiness of $0$, but it can be computed efficiently in a similar manner, using its segments of coin receiving and some partial sums.
The final complexity is $O(N)$ because we can obtain in $O(N)$ all the precomputations about $I(0)$ and $I(N)$ and we can print each of the $N + 1$ numbers using $O(1)$ time.
h3. Request
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The final complexity is $O(N)$ because we can obtain in $O(N)$ all the precomputations about $I(0)$ and $I(N)$ and we can print each of the $N + 1$ numbers using $O(1)$ time.
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