return _cubicRoot(c)
==

This is still slow when we’re dealing with large numbers. To address it one can binary search first on the exponent, or get close to the real exponent by dividing the original exponent by 3. Try it out in the comment section.

This is still slow when we’re dealing with large numbers. To address that one can binary search on the exponent of the result and then on the mantissa of the result.  Try it out in the comment section.

bq. I'm curious, did your solution have any of these problems?