Diferente pentru blog/meet-in-the-middle intre reviziile #12 si #13

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If we find any match in the two sets it means that Ek1(p) = Dk2(s) so the secret keys are k1 and k2.
The naive brute force algorithm would go through 2^56 * 2^56 iterations by brute forcing through all possible values of k1 and k2 while this algorithm uses 2^56 * 56 memory to store Ek(p) and does O(2^56) work to find a match.
h2. the discrete logarithm problem
h2. Discrete logarithm
bq. Given n a prime number and p, q two integer numbers between 0 and n-1 find k such that  p^k = q modulo n.

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