//ultima cifra a sumei pow 1,1 + 22 + ... + NN.
#include <stdio.h>
#include <string.h>
char n[101];
long i,j,k,s,t,d;
long c[]={0,1,5,2,8,3,9,2,8,7,7,8,4,7,3,8,4,1,5,4,4,5,9,6,2,7,3,6,2,1,1,2,8,1,7,2,8,5,9,8,8,9,3,0,6,1,7,0,6,5,5,6,2,5,1,6,2,9,3,2,2,3,7,4,0,5,1,4,0,9,9,0,6,9,5,0,6,3,7,6,6,7,1,8,4,9,5,8,4,3,3,4,0,3,9,4,0,7,1,0,0};

int main ()
{   freopen("cifra.in","r",stdin);

freopen("cifra.out","w",stdout);
scanf("%ld",&t);
for(i=0;i<t;++i)
{
k=0;
scanf("%s",&n);
d=strlen(n);
if(d>1)
{   k+=n[d-2]-'0';
k*=10;
k+=n[d-1]-'0';
}
else

k=n[d-1]-'0';

printf("%ld\n",c[k]);
}

return 0;
}