#include <iostream>
#include <cmath>
#include <fstream>
using namespace std;
ifstream in("sumdiv.in");
ofstream out("sumdiv.out");

int main()
{
    long long d = 2, n, p, e, s = 1;
    in >> n >> p;
    while(n > 1){
        e = 0;
        while(n % d == 0){
            e++;
            n /= d;
        }
        if(e > 0){
            s = s * ( (pow(d, e * p + 1) - 1) / (d - 1) );
            s = s % 9901;
        }
    }
    out << s;
    return 0;
}