Cod sursa(job #2902797)

Utilizator Teodor_AxinteAxinte Teodor-Ionut Teodor_Axinte Data 16 mai 2022 20:34:46
Problema Range minimum query Scor 0
Compilator cpp-64 Status done
Runda Arhiva educationala Marime 2.25 kb
#include <fstream>
#include <iostream>

using namespace std;

ifstream fin("rmq.in");
ofstream fout("rmq.out");
/*
const int oo = INT32_MAX;
const int N = 500010;

int n, m, o, a, b;
int input[N], segTree[4 * N + 10];

void constructTree(int input[], int segTree[], int low, int high, int pos)
{
    if (low == high)
    {
        segTree[pos] = input[low];
        return;
    }
    int mid = (low + high) / 2;
    // if (pos <= mid)
    constructTree(input, segTree, low, mid, 2 * pos + 1);
    // else
    constructTree(input, segTree, mid + 1, high, 2 * pos + 2);
    segTree[pos] = min(segTree[2 * pos + 1], segTree[2 * pos + 2]);
}

int rangeMinQuery(int segTree[], int Qlow, int Qhigh, int low, int high, int pos)
{
    if (Qlow <= low && Qhigh >= high) // total overlap
        return segTree[pos];
    if (Qlow > high || Qhigh < low) // no overlap
        return oo;
    int mid = (low + high) / 2;
    return min(rangeMinQuery(segTree, Qlow, Qhigh, low, mid, 2 * pos + 1),
               rangeMinQuery(segTree, Qlow, Qhigh, mid + 1, high, 2 * pos + 2)); // double overlap
}

int main()
{
    fin >> n >> m;
    for (int i = 0; i < n; i++)
        fin >> input[i];
    for (int i = 0; i < 4 * n; i++)
        segTree[i] = oo;
    constructTree(input, segTree, 0, n - 1, 0);

    for (int i = 0; i < 4 * n; i++)
        cout << segTree[i] << " ";

    for (; m != 0; m--)
    {
        fin >> a >> b;
        fout << rangeMinQuery(segTree, a - 1, b - 1, 0, n - 1, 0) << '\n';
    }
    return 0;
}
*/

const int N = 100001;
int n, m, x, y, l, dif, shift;
int lg[N], a[N];
int rmq[18][N];

int main()
{
    fin >> n >> m;
    for (int i = 1; i <= n; i++)
        fin >> a[i];
    for (int i = 2; i <= n; i++)
        lg[i] = lg[i / 2] + 1;
    for (int i = 1; i <= n; i++)
        rmq[0][i] = a[i];

    for (int i = 1; i <= n; i++)
        for (int j = 1; j <= n - (1 << i) + 1; j++)
        {
            l = 1 << (i - 1);
            rmq[i][j] = min(rmq[i - 1][j], rmq[i - 1][j + 1]);
        }

    for (int i = 1; i <= m; i++)
    {
        fin >> x >> y;
        dif = y - x + 1;
        l = lg[dif];
        shift = dif - (1 << l);
        fout << min(rmq[l][x], rmq[l][x + shift]) << '\n';
    }
}